RunUO Community
This is a sample guest message. Register a free account today to become a member! Once signed in, you'll be able to participate on this site by adding your own topics and posts, as well as connect with other members through your own private inbox!
Here...
- Thread starter Xenon
- Start date
No one interested?
Start with all numbers n > or = 4. f4/f3=1.5, and f5/f4=1.67, so only concern cases where n > or = 6. Assume that we solve for fk/fk-1 such that 4 < or = 4 < or = n-1. This means we can say that fn-1/fn-2 < 1.7 and fn-2/fn-3 < 1.7, and we can say k=n-1 and k=n-2, since they both fit the parameter 4 < or = k < or = n-1. Therefore, fn-1 < (1.7)fn-2 and )fn-2 < (1.7)fn-3, which means
fn = fn + fn-2 < (1.7)fn-2 + (1.7)fn-3 = (1.7)(fn-2 + fn-3) = (1.7)fn-1.
By induction, the problem is solved
Start with all numbers n > or = 4. f4/f3=1.5, and f5/f4=1.67, so only concern cases where n > or = 6. Assume that we solve for fk/fk-1 such that 4 < or = 4 < or = n-1. This means we can say that fn-1/fn-2 < 1.7 and fn-2/fn-3 < 1.7, and we can say k=n-1 and k=n-2, since they both fit the parameter 4 < or = k < or = n-1. Therefore, fn-1 < (1.7)fn-2 and )fn-2 < (1.7)fn-3, which means
fn = fn + fn-2 < (1.7)fn-2 + (1.7)fn-3 = (1.7)(fn-2 + fn-3) = (1.7)fn-1.
By induction, the problem is solved
C
Chaos
Guest
I use basic high school math when I program
Hence, my programs usually suck.
Hence, my programs usually suck.