help with Variables?? - RunUO

Atrus · 01-24-2003, 04:51 PM

how difficult/involved would it be to change

(static) int Random( int from, int count )

to

(static) double Random( double from, double count ) ??

my hope is to allow a decimal to be used in the random...also am I reading that

this.Skills[SkillName.MagicResist].Base = Utility.Random(20,40);

is giving me a value randomly from 20 to 40??

Spooky · 01-24-2003, 08:05 PM

this.Skills[SkillName.MagicResist].Base = Utility.Random(20,40)

the above code produces a random number from 19 - 59
the first number is the minimum the second is the stepping.
remember that numbering starts at 0.

you can convert an Int to a double but only if that data type in runUO supports it.

Atrus · 01-25-2003, 03:13 PM

ok how do I get a value from 20-40??

**krrios** · 01-25-2003, 03:33 PM

Utility.RandomMinMax( 20, 40 );

Atrus · 01-25-2003, 04:05 PM

thank you very much...I probly looked right over that one when I was looking

Atrus · 01-25-2003, 04:10 PM

also how tough/involved would it be to change
(static) int RandomMinMax( int min, int max )
to
(static) double RandomMinMax( double min, double max )
since it currently doesn't allow doubles

mrkroket · 01-25-2003, 04:31 PM

You always can do fixed point math with integers. To use let's say 2 decimals, multiply all your real values by 100, and convert it to integers.
After all integer calculations, convert to double and divide it by 100.

(double) (RandomMinMax( (int) (min*100), (int) (max*100) ) ) / 100

**Zippy** · 01-25-2003, 04:34 PM

You could also do:

(double)(Utility.Random( 5, 6 )) + Utility.RandomDouble();

this would give you a random from 4 to 9.999999999

Random double returns a random double from 0 to 0.99999999

Atrus · 01-25-2003, 05:06 PM

ok I like those sudjestions but could you tell me where to find
(static) int RandomMinMax( int min, int max )
so I can try that...I found it in the Documentation files

01-24-2003, 04:51 PM	#1 (permalink)
Atrus Join Date: Jan 2003 Posts: 80	help with Variables?? how difficult/involved would it be to change (static) int Random( int from, int count ) to (static) double Random( double from, double count ) ?? my hope is to allow a decimal to be used in the random...also am I reading that this.Skills[SkillName.MagicResist].Base = Utility.Random(20,40); is giving me a value randomly from 20 to 40??

01-25-2003, 04:34 PM	#8 (permalink)
Zippy Administrator Join Date: Aug 2002 Location: Baltimore, MD Age: 25 Posts: 4,870	You could also do: (double)(Utility.Random( 5, 6 )) + Utility.RandomDouble(); this would give you a random from 4 to 9.999999999 Random double returns a random double from 0 to 0.99999999 __________________ Zippy, Razor Creator and RunUO Core Developer The RunUO Software Team "Intuition, like a flash of lightning, lasts only for a second. It generally comes when one is tormented by a difficult decipherment and when one reviews in his mind the fruitless experiments already tried. Suddenly the light breaks through and one finds after a few minutes what previous days of labor were unable to reveal." ~The Cryptonomicon

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01-24-2003, 08:05 PM	#2 (permalink)
Spooky Forum Expert Join Date: Sep 2002 Posts: 1,267	this.Skills[SkillName.MagicResist].Base = Utility.Random(20,40) the above code produces a random number from 19 - 59 the first number is the minimum the second is the stepping. remember that numbering starts at 0. you can convert an Int to a double but only if that data type in runUO supports it.

01-25-2003, 03:13 PM	#3 (permalink)
Atrus Join Date: Jan 2003 Posts: 80	ok how do I get a value from 20-40??

01-25-2003, 03:33 PM	#4 (permalink)
krrios Forum Administrator Join Date: Aug 2002 Posts: 2,850	Utility.RandomMinMax( 20, 40 );

01-25-2003, 04:05 PM	#5 (permalink)
Atrus Join Date: Jan 2003 Posts: 80	thank you very much...I probly looked right over that one when I was looking

01-25-2003, 04:10 PM	#6 (permalink)
Atrus Join Date: Jan 2003 Posts: 80	also how tough/involved would it be to change (static) int RandomMinMax( int min, int max ) to (static) double RandomMinMax( double min, double max ) since it currently doesn't allow doubles

01-25-2003, 04:31 PM	#7 (permalink)
mrkroket Join Date: Dec 2002 Posts: 140	You always can do fixed point math with integers. To use let's say 2 decimals, multiply all your real values by 100, and convert it to integers. After all integer calculations, convert to double and divide it by 100. (double) (RandomMinMax( (int) (min100), (int) (max100) ) ) / 100

01-25-2003, 05:06 PM	#9 (permalink)
Atrus Join Date: Jan 2003 Posts: 80	ok I like those sudjestions but could you tell me where to find (static) int RandomMinMax( int min, int max ) so I can try that...I found it in the Documentation files

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