Issue with TimeClock, Can someone Help? :)

Ignacio Vazquez-Abrams · Feb 19, 2004

awakenlands said:
i have net 1.1 sdk hehe

why i need it? I have no clue what it does

You use it for the documentation. I'm sure the rest of it has its uses, I just don't know what.

Ravenal · Feb 19, 2004

well i have the docs in my type folders and stuff is that what you talking about? cuz i do use it

Ignacio Vazquez-Abrams · Feb 19, 2004

That's the RunUO documentation. I'm talking about the .NET Framework documentation. Hint: check Start | Programs.

Ravenal · Feb 19, 2004

So do i just look up DateTime???

Cuz it told me this, which i am like HUH!?

PHP:

class DateTimeTester {

    static bool RoughlyEquals(DateTime time, DateTime timeWithWindow, int windowInSeconds, int frequencyInSeconds)
    {

            long delta = (long)((TimeSpan)(timeWithWindow - time)).TotalSeconds % frequencyInSeconds;

            delta = delta > windowInSeconds ? frequencyInSeconds - delta : delta;

            return Math.Abs(delta) < windowInSeconds;

    }

    public static void Main() 
    {
            int window = 10;
            int freq = 60 * 60 * 2; // 2 hours;

            DateTime d1 = DateTime.Now;

            DateTime d2 = d1.AddSeconds(2 * window);
            DateTime d3 = d1.AddSeconds(-2 * window);
            DateTime d4 = d1.AddSeconds(window / 2);
            DateTime d5 = d1.AddSeconds(-window / 2);

            DateTime d6 = (d1.AddHours(2)).AddSeconds(2 * window);
            DateTime d7 = (d1.AddHours(2)).AddSeconds(-2 * window);
            DateTime d8 = (d1.AddHours(2)).AddSeconds(window / 2);
            DateTime d9 = (d1.AddHours(2)).AddSeconds(-window / 2);

            Console.WriteLine("d1 ~= d1 [true]: " + RoughlyEquals(d1, d1, window, freq));
            Console.WriteLine("d1 ~= d2 [false]: " + RoughlyEquals(d1, d2, window, freq));
            Console.WriteLine("d1 ~= d3 [false]: " + RoughlyEquals(d1, d3, window, freq));
            Console.WriteLine("d1 ~= d4 [true]: " + RoughlyEquals(d1, d4, window, freq));
            Console.WriteLine("d1 ~= d5 [true]: " + RoughlyEquals(d1, d5, window, freq));

            Console.WriteLine("d1 ~= d6 [false]: " + RoughlyEquals(d1, d6, window, freq));
            Console.WriteLine("d1 ~= d7 [false]: " + RoughlyEquals(d1, d7, window, freq));
            Console.WriteLine("d1 ~= d8 [true]: " + RoughlyEquals(d1, d8, window, freq));
            Console.WriteLine("d1 ~= d9 [true]: " + RoughlyEquals(d1, d9, window, freq));


    }
}

Ravenal · Feb 19, 2004

ok i found this now. is this what i should be looking at??? to make?

PHP:

using System;
using System.Globalization;


public class SamplesCalendar  {

   public static void Main()  {

      // Sets a DateTime to April 3, 2002 of the Gregorian calendar.
      DateTime myDT = new DateTime( 2002, 4, 3, new GregorianCalendar() );

      // Uses the default calendar of the InvariantCulture.
      Calendar myCal = CultureInfo.InvariantCulture.Calendar;

      // Displays the values of the DateTime.
      Console.WriteLine( "April 3, 2002 of the Gregorian calendar:" );
      DisplayValues( myCal, myDT );

      // Adds 5 to every component of the DateTime.
      myDT = myCal.AddYears( myDT, 5 );
      myDT = myCal.AddMonths( myDT, 5 );
      myDT = myCal.AddWeeks( myDT, 5 );
      myDT = myCal.AddDays( myDT, 5 );
      myDT = myCal.AddHours( myDT, 5 );
      myDT = myCal.AddMinutes( myDT, 5 );
      myDT = myCal.AddSeconds( myDT, 5 );
      myDT = myCal.AddMilliseconds( myDT, 5 );

      // Displays the values of the DateTime.
      Console.WriteLine( "After adding 5 to each component of the DateTime:" );
      DisplayValues( myCal, myDT );

   }

   public static void DisplayValues( Calendar myCal, DateTime myDT )  {
      Console.WriteLine( "   Era:          {0}", myCal.GetEra( myDT ) );
      Console.WriteLine( "   Year:         {0}", myCal.GetYear( myDT ) );
      Console.WriteLine( "   Month:        {0}", myCal.GetMonth( myDT ) );
      Console.WriteLine( "   DayOfYear:    {0}", myCal.GetDayOfYear( myDT ) );
      Console.WriteLine( "   DayOfMonth:   {0}", myCal.GetDayOfMonth( myDT ) );
      Console.WriteLine( "   DayOfWeek:    {0}", myCal.GetDayOfWeek( myDT ) );
      Console.WriteLine( "   Hour:         {0}", myCal.GetHour( myDT ) );
      Console.WriteLine( "   Minute:       {0}", myCal.GetMinute( myDT ) );
      Console.WriteLine( "   Second:       {0}", myCal.GetSecond( myDT ) );
      Console.WriteLine( "   Milliseconds: {0}", myCal.GetMilliseconds( myDT ) );
      Console.WriteLine();
   }

}


/*
This code produces the following output.

April 3, 2002 of the Gregorian calendar:
   Era:          1
   Year:         2002
   Month:        4
   DayOfYear:    93
   DayOfMonth:   3
   DayOfWeek:    Wednesday
   Hour:         0
   Minute:       0
   Second:       0
   Milliseconds: 0

After adding 5 to each component of the DateTime:
   Era:          1
   Year:         2007
   Month:        10
   DayOfYear:    286
   DayOfMonth:   13
   DayOfWeek:    Saturday
   Hour:         5
   Minute:       5
   Second:       5
   Milliseconds: 5

*/

Ravenal · Feb 19, 2004

So if i want

Code:

private static DateTime WorldStart = new DateTime( 1997, 9, 1 );

to be this

Code:

private static DateTime WorldStart = new DateTime( 22878, 1, 1 );

I gotta fix this???

PHP:

public static void GetTime( Map map, int x, int y, out int hours, out int minutes, out int totalMinutes )
		{
			TimeSpan timeSpan = DateTime.Now - WorldStart;

			totalMinutes = (int)(timeSpan.TotalSeconds / SecondsPerALMinute);

			if ( map != null )
				totalMinutes += map.MapIndex * 320;

			totalMinutes += x / 16;

			hours = (totalMinutes / 60) % 24;
			minutes = totalMinutes % 60;
		}

Ravenal · Feb 20, 2004

well?? anyone??? I mean no one responded to my question for the last 24 hours

Ignacio Vazquez-Abrams · Feb 20, 2004

What you need to do is change the variable type in your code from TimeSpan to something that can hold more than 24 hours in it.

Why do you use TimeSpan instead of DateTime?

Ravenal · Feb 20, 2004

so should i not use DateTime.Now, and just get rid of it and just use WorldTime???

so like this?

PHP:

public const double SecondsPerALMinute = 4;
public const double MinutesPerALDay = SecondsPerALMinute * 24;

private static DateTime WorldStart = new DateTime( 22585, 1, 1 );

PHP:

public static void GetTime( Map map, int x, int y, out int hours, out int minutes, out int totalMinutes )
		{
			TimeSpan timeSpan = WorldStart;

			totalMinutes = (int)(timeSpan.TotalSeconds / SecondsPerALMinute);

			if ( map != null )
				totalMinutes += map.MapIndex * 320;

			totalMinutes += x / 16;

			hours = (totalMinutes / 60) % 24;
			minutes = totalMinutes % 60;
		}

Ignacio Vazquez-Abrams · Feb 20, 2004

awakenlands said:
so should i not use DateTime.Now, and just get rid of it and just use WorldTime???

No, what you should do is get rid of TimeSpan and just use DateTime.

Ravenal · Feb 20, 2004

so do this?

PHP:

public static void GetTime( Map map, int x, int y, out int hours, out int minutes, out int totalMinutes )
		{
			DateTime.Now - WorldStart;

			totalMinutes = (int)(SecondsPerALMinute);

			if ( map != null )
				totalMinutes += map.MapIndex * 320;

			totalMinutes += x / 16;

			hours = (totalMinutes / 60) % 24;
			minutes = totalMinutes % 60;
		}

Ignacio Vazquez-Abrams · Feb 20, 2004

No.

Code:

DateTime timeSpan = DateTime.Now - WorldStart;

Ravenal · Feb 20, 2004

I change it and it gives me this error

Code:

 - Error: Scripts\Items\Skill Items\Tinkering\Clocks.cs: CS0029: (line 74, colum
n 24) Cannot implicitly convert type 'System.TimeSpan' to 'System.DateTime'

Ignacio Vazquez-Abrams · Feb 20, 2004

Gather 'round kids, it's time for an important lesson!

Don't always take other people's word for it, especially when you've seen the be wrong at other stuff.

I did some double-checking, and it turns out that TimeSpan is NOT limited to a 24-hour period. It also has a convenient little member called days.

Okay, change it back into a TimeSpan, figure out how many ALdays have passed since midnight, then figure out how many ALdays are contained in the days field.

Ravenal · Feb 20, 2004

so you mean to find how many ALDays there are within our 24 hour period?

Ignacio Vazquez-Abrams · Feb 21, 2004

Pretty much.

Ravenal · Feb 21, 2004

Okay this is the exact List of our Awakenlands Days, Year, Months and Hours, Seconds, and Minutes of our time and our world time....

PHP:

1 Min of ALMinute = 4 Seconds Real Time
60 Mins of ALMinutes = 240 Seconds Real Time
24 Hours of ALMinutes  = 5760 Seconds Real Time
42 Days of ALMinutes = 241920 Seconds Real Time
11 Months of ALMinutes = 2661120 Seconds Real Time
1 Year of ALMinutes = 2661120 Seconds Real Time

1 Hour of ALHours = 4 Minutes Real Time
24 Hours of ALHours = 240 Minutes Real Time
42 Days of ALHours = 5760 Minutes Real Time
11 Months of ALHours = 241920 Minutes Real Time
1 Year of ALHours = 241920 Minutes Real Time

1 Days of ALDays = 10 Hours of Real Time
42 Days of ALDays = 137 Hours of Real Time
11 Months of ALDays = 21993 Hours of Real Time
1 Year of ALDays = 21993 Hours of Real Time

1 Month of ALMonth = 3 Days of Real Time
11 Months of ALMonths = 33 Days of Real Time
1 Year of ALMonths = 33 Days of Real Time

1 Year of ALYears = 1 Month and 3 Days of Real Time

Ignacio Vazquez-Abrams · Feb 21, 2004

awakenlands said:
1 Days of ALDays = 10 Hours of Real Time

Okay, so then take days, multiply it by 2.4, the whole number is ALDays, and the fractional part needs to be converted to ALHours and ALMinutes and added to what you have so far.

Ravenal · Feb 21, 2004

so you mean to take 2.4 * it by 10 hours???? which is 24 hours...

Ravenal · Feb 21, 2004

oh you mean days, so 1 day * 2.4 is 2.4 days, so what you wnat me to do with that?

Issue with TimeClock, Can someone Help? :)

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